Slurry density calculation: complete example at 40 wt% solids and 100 m³/h

A complete worked example for slurry density, solids volume fraction, dry-solids throughput and liquid flow using fictional data.

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This example manually verifies the main outputs of the Minerallum calculator.

All values are fictional and are used only to explain the method.

Starting data

Assume a simple two-phase slurry:

  • solid particles;
  • carrier liquid;
  • no significant entrained air.

Inputs:

ρs=2650kg/m3\rho_s=2650\ kg/m^3
ρl=1000kg/m3\rho_l=1000\ kg/m^3

Solids by mass:

w=40%=0.40w=40\%=0.40

Slurry volumetric flow:

Q=100m3/hQ=100\ m^3/h

Step 1 - calculate slurry density

ρm=1wρs+1-wρl\rho_m= \frac{1}{ \frac{w}{\rho_s} + \frac{1-w}{\rho_l} }

Substitute:

ρm=10.40/2650+0.60/1000\rho_m= \frac{1}{ 0.40/2650+ 0.60/1000 }

Terms:

0.40/2650=0.000150943396...0.40/2650 = 0.000150943396...
0.60/1000=0.00060.60/1000 = 0.0006

Sum:

0.000750943396...0.000750943396...

Therefore:

ρm=1331.658291457...kg/m3\rho_m= 1331.658291457... \ kg/m^3

Result:

1331.6583kg/m3\boxed{1331.6583\ kg/m^3}

Step 2 - calculate solids by volume

φ=wρmρs\phi= \frac{w\rho_m}{\rho_s}
φ=0.40×1331.6582914572650\phi= \frac{ 0.40\times1331.658291457 }{ 2650 }
φ=0.201005025126...\phi= 0.201005025126...

Therefore:

20.1005% solids by volume\boxed{20.1005\% \text{ solids by volume}}

This immediately shows why 40 wt% is not 40 vol%.

Step 3 - verify density using the volume-fraction form

ρm=φρs+(1-φ)ρl\rho_m= \phi\rho_s+ (1-\phi)\rho_l
ρm=0.201005025126×2650+0.798994974874×1000\rho_m= 0.201005025126\times2650 + 0.798994974874\times1000

Solid contribution:

532.663316583kg/m3532.663316583\ kg/m^3

Liquid contribution:

798.994974874kg/m3798.994974874\ kg/m^3

Total:

1331.658291457kg/m31331.658291457\ kg/m^3

The same density is recovered.

Step 4 - total slurry mass flow

mm˙=Qρm\dot m_m=Q\rho_m
mm˙=100×1331.658291457\dot m_m= 100\times1331.658291457
mm˙=133165.829145729kg/h\dot m_m= 133165.829145729\ kg/h

or:

133.165829t/h\boxed{133.165829\ t/h}

Step 5 - dry-solids flow

ms˙=Qρmw\dot m_s= Q\rho_mw
ms˙=100×1331.658291457×0.40\dot m_s= 100\times1331.658291457\times0.40
ms˙=53266.331658291kg/h\dot m_s= 53266.331658291\ kg/h

or:

53.266332t/h\boxed{53.266332\ t/h}

Step 6 - cross-check dry-solids flow from volume fraction

ms˙=Qφρs\dot m_s= Q\phi\rho_s
ms˙=100×0.201005025126×2650\dot m_s= 100\times0.201005025126\times2650
ms˙=53266.331658291kg/h\dot m_s= 53266.331658291\ kg/h

The independent form gives the same result.

This is a useful software invariant.

Step 7 - liquid mass flow

ml˙=Qρm(1-w)\dot m_l= Q\rho_m(1-w)
ml˙=100×1331.658291457×0.60\dot m_l= 100\times1331.658291457\times0.60
ml˙=79899.497487437kg/h\dot m_l= 79899.497487437\ kg/h

or:

79.899497t/h\boxed{79.899497\ t/h}

Step 8 - mass closure

53.266331658+79.899497487=133.165829145t/h53.266331658 + 79.899497487 = 133.165829145\ t/h

The total slurry mass flow closes.

Step 9 - phase volume flows

Solids:

Qs=QφQ_s=Q\phi
Qs=100×0.201005025126Q_s= 100\times0.201005025126
Qs=20.100503m3/h\boxed{Q_s=20.100503\ m^3/h}

Liquid:

Ql=Q(1-φ)Q_l=Q(1-\phi)
Ql=100×0.798994974874Q_l= 100\times0.798994974874
Ql=79.899497m3/h\boxed{Q_l=79.899497\ m^3/h}

Check:

Qs+Ql=100m3/hQ_s+Q_l=100\ m^3/h

Step 10 - dilution ratio

D=1-wwD= \frac{1-w}{w}
D=0.600.40D= \frac{0.60}{0.40}
D=1.5\boxed{D=1.5}

The example contains 1.5 units of liquid mass per unit dry-solids mass.

Results summary

Quantity Result
Slurry density 1331.6583 kg/m³
Solids by mass 40.0000%
Solids by volume 20.1005%
Liquid by mass 60.0000%
Liquid by volume 79.8995%
Total slurry mass flow 133.1658 t/h
Dry-solids flow 53.2663 t/h
Liquid mass flow 79.8995 t/h
Solid volume flow 20.1005 m³/h
Liquid volume flow 79.8995 m³/h
Dilution ratio 1.5

Reverse check: recover 40 wt% from slurry density

Now assume we know:

  • ρs = 2650 kg/m³
  • ρl = 1000 kg/m³
  • ρm = 1331.658291457 kg/m³

Use:

w=ρs(ρm-ρl)ρm(ρs-ρl)w= \frac{ \rho_s(\rho_m-\rho_l) }{ \rho_m(\rho_s-\rho_l) }

Substituting returns:

w=0.40w=0.40

or:

40%40\%

The forward and inverse calculations are consistent.

Why this does not size a pump

The example provides:

  • densities;
  • concentration;
  • volumetric flow.

It does not necessarily provide:

  • viscosity;
  • rheology;
  • particle-size distribution;
  • deposition velocity;
  • pipe friction;
  • pipe diameter/length;
  • elevation;
  • NPSH;
  • entrained gas.

It would therefore be incorrect to convert this calculation into a pump or pipeline recommendation.

Minerallum deliberately keeps the tool limited to composition and derived flows.

Entrained-air warning

If the measured density contains a significant gas void fraction, it can be lower than the true solid-liquid slurry density.

This example contains no gas phase.

Do not blindly use an aerated bulk-density measurement as ρm in this two-phase calculation.

Privacy

The intended Minerallum implementation performs the calculation locally.

Technical input values are not stored by Minerallum or transmitted to analytics.

The contact CTA does not automatically carry the user’s calculation data.

References

  1. Wills, B. A.; Finch, J. Wills’ Mineral Processing Technology, 8th edition, Chapter 3. https://doi.org/10.1016/C2010-0-65478-2
  2. Scelzo, M. T. et al. (2021). Design and validation of a capacitance-based sensor for slurry density measurement. https://doi.org/10.1016/j.expthermflusci.2020.110299
  3. Bamberger, J. A.; Greenwood, M. S. (2004). Using ultrasonic attenuation to monitor slurry mixing in real time. https://doi.org/10.1016/j.ultras.2004.02.016

Use the calculator

Enter your own phase densities and known concentration/density.

Open Show calculation to inspect every substitution.

This guide uses fictional values and is not equipment sizing, process validation or engineering approval.

Documentation

Sources and references

The technical information presented in this article is based on the following publications and resources.

  1. 01
    Elsevier

    Wills? Mineral Processing Technology, Chapter 3

    View source
  2. 02
    Experimental Thermal and Fluid Science

    Scelzo et al. (2021), Slurry density measurement

    View source
  3. 03
    Ultrasonics / PNNL

    Bamberger & Greenwood (2004), Slurry mixing

    View source

Technical requirements may vary depending on the installation, applicable standards, process and system-designer recommendations.